26x^2-22x-30=0

Solution for 26x^2-22x-30=0 equation:

26x^2-22x-30=0

a = 26; b = -22; c = -30;
Δ = b2-4ac
Δ = -222-4·26·(-30)
Δ = 3604
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{3604}=\sqrt{4*901}=\sqrt{4}*\sqrt{901}=2\sqrt{901}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-22)-2\sqrt{901}}{2*26}=\frac{22-2\sqrt{901}}{52}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-22)+2\sqrt{901}}{2*26}=\frac{22+2\sqrt{901}}{52}
$